If m and σ2 are the mean and variance of the random variable X whose distributions given by: X=x : 0 1 2 3 P(X=x) : 1/3 1/2 0 1/6

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m=σ2=2

m=1,σ2=2

m=σ2=1

m=2,σ2=1

answer is C.

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Detailed Solution

m=∑xP(X=x)=0(1/3)+1(1/2)+2(0)+3(1/6)=0+1/2+0+1/2=1 σ2=∑x2P(X=x)−m2=02(1/3)+12(1/2)+22(0)+32(1/6)−12 =0+1/2+0+3/2−1=2−1=1

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