If (m;, 1/m;),i = 1,2,3,4 are concyclic points, then the value of m1 m2 m3 m4, is
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a
1
b
-1
c
0
d
none of these
answer is A.
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Detailed Solution
Let the equation of the circle bex2+y2+2gx+2yy+c=0.If (m, 1 Im) Lies on this circle, thenm2+1m2+2gm+2f1m+c=0⇒ m4+2gm3+2fm+cm2+1=0This is a fourth degree equation in m having m1,m2,m3,m4 as its roots.∴ Product of the roots =1⇒m1m2m3m4=11=1