First slide
Theory of equations
Question

 If mr,1mr;r=1,2,3,4 are four pairs of values of x and y that satisfy the equation 

x2+y2+2gx+2fy+c=0, then value of m1m2m3m4

Moderate
Solution

mr,1mr satisfy the given equation x2+y2+2gx+2fy+c=0

 then mr2+1mr2+2gmr+2fmr+c=0

 mr4+2gmr3+cmr2+2fmr+1=0

 Now roots of given equation are m1,m2,m3,m4

 Product of roots =m1m2m3m4

= constant term  coefficeint of mr4=11=1

 

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