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$If the matrices A = [\begin{array}{l} 1 & 1 & 2 \\ 1 & 3 & 4 \\ 1 & - 1 & 3 \end{array}], B = a d j A and C = 3 A, then \frac{| a d j B |}{| C |} is equal to:$

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Correct option is C

We have A=1121341−13=9+4−13−4+2−1−3=13+1−8=6|adjB|=|adj(adjA)|=|adjA|n-1=|A|(n-1)2=|A|4=64 and |C|=|3A|=33×6 Hence, |adjB||C|=6433×6=8

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If the matrices A=1121341-13,B=adjA and C=3A , then |adjB||C| is equal to:

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$If the matrices A = [\begin{array}{l} 1 & 1 & 2 \\ 1 & 3 & 4 \\ 1 & - 1 & 3 \end{array}], B = a d j A and C = 3 A, then \frac{| a d j B |}{| C |} is equal to:$