Q.
If matrix A=[aij]3x3 , matrix B=[bij]3x3 , where aij+aji=0 and bij−bji=0 ∀i,j, then A4.B3 is
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a
Singular
b
zero matrix
c
Symmetric
d
Skew-symmetric matrix
answer is A.
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Detailed Solution
Here aij+aji=0⇒AT=−A & bij−bji=0⇒BT=B and A, B are 3×3 matrices. Hence |A|=0⇒|A4B3|=0⇒A4B3 is singular matrix.
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