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$If the matrix [\begin{array}{ccc} 1 & - 1 & 2 \\ 3 & 2 & 1 \\ - 1 & α & 3 \end{array}] is singular then α =$

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Correct option is C

⇒6−α+1(9+1)+2(3α+2)=0⇒6−α+10+6α+4=0⇒5α+20=0⇒α=−4

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If the matrix 1−12321−1α3 is singular then α=

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$If the matrix [\begin{array}{ccc} 1 & - 1 & 2 \\ 3 & 2 & 1 \\ - 1 & α & 3 \end{array}] is singular then α =$