If the mean deviation of numbers  1, 1+d,1+2d, ………1+100d from their mean is 255,then the d is equal to

(x¯)= Sum of quantities n=n2(a+l)n=12(1+1+100d)=1+50d∴MD=1n∑xi−x¯⇒255=1101(50d+49d+48d+…+d+0+d+…+50d)=2d10150×512⇒ d=255×10150×51=10.1