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If the mean of first n natural numbers is $\frac{5 n}{9},$

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Correct option is C

It is given that1+2+3+…+nn=5n9⇒n+12=5n9⇒n=9

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Variate x	1	2	3	4	5
Frequency f of x	4	5	y	1	2

If the mean of first n natural numbers is 5n9,

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If the mean of first n natural numbers is $\frac{5 n}{9},$