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If the mean of first n odd natural numbers is $\frac{n^{2}}{81},$

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Correct option is B

It is given that1+3+5+7+…+(2n−1)n=n281⇒n2n=n281⇒n=81

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Variate x	1	2	3	4	5
Frequency f of x	4	5	y	1	2

If the mean of first n odd natural numbers is n281,

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If the mean of first n odd natural numbers is $\frac{n^{2}}{81},$