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If the mean of nobsenrations1² ,2²,3²………n² is $\frac{46 n}{11}$ , then n is equal to

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Correct option is A

According to the given condition,12+22+32+…+n2n=46n11⇒n(n+1)(2n+1)6n=46n11⇒112n2+3n+1=276n⇒22n2−243n+11=0⇒(n−11)(22n−1)=0⇒n=11

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Variate x	1	2	3	4	5
Frequency f of x	4	5	y	1	2

If the mean of nobsenrations12 ,22,32………n2 is 46n11, then n is equal to

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If the mean of nobsenrations1² ,2²,3²………n² is $\frac{46 n}{11}$ , then n is equal to