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$If the mean of the numbers 27 + x, 31 + x, 89 + x, 107 + x, 156 + x i s 82, t h e n t h e m e a n o f 130 + x, 126 + x, 68 + x, 50 + x, 1 + x i s$

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Correct option is A

Given82=(27+x)+(31+x)+(89+x)+(107+x)+(156+x)5⇒ 82×5=410+5x⇒410−410=5x⇒x=0Therefore, the required mean is x¯=130+x+126+x+68+x+50+x+1+x5=375+5x5=375+05=3755=75

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Variate x	1	2	3	4	5
Frequency f of x	4	5	y	1	2

If the mean of the numbers 27+x,31+x,89+x,107+x,156+x is 82 ,then the mean of 130+x,126+x,68+x,50+x,1+x is

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$If the mean of the numbers 27 + x, 31 + x, 89 + x, 107 + x, 156 + x i s 82, t h e n t h e m e a n o f 130 + x, 126 + x, 68 + x, 50 + x, 1 + x i s$