If the mean of the set of numbers x1,x2,…,xn is x¯, then the mean of the numbers xi+2i,1≤i≤n is
x¯+2n
x¯+n+1
x¯+2
x¯+n
x¯=1n∑i=1n xi⇒ ∑i=1n xi=nx¯ Let M=1n∑i=1n xi+2i=1n∑i=1n xi+2(1+2+…+n)n⇒ M=1nnx¯+2n(n+1)2n∴ M=x¯+(n+1)