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$If the mean of the set of numbers x_{1}, x_{2}, x_{3}, \dots, x_{n} is \bar{x}, then the mean of the numbers x_{i} + 2 i, 1 \leq i \leq n is$

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Correct option is B

We know that x¯=∑i=1n xin⇒∑i=1n xi=nx¯∴∑i=1n xi+2in=∑i=1n xi+2∑i=1n in=nx¯+2(1+2+…n)n=nx¯+2n(n+1)2n=x¯+(n+1)

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Variate x	1	2	3	4	5
Frequency f of x	4	5	y	1	2

If the mean of the set of numbers x1,x2,x3,…,xn is x¯ , then the mean of the numbers xi+2i,1≤i≤n is

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$If the mean of the set of numbers x_{1}, x_{2}, x_{3}, \dots, x_{n} is \bar{x}, then the mean of the numbers x_{i} + 2 i, 1 \leq i \leq n is$