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If the mean and standard deviation of 5 observations x1, x2, x3, x4, x5 are 10 and 3 respectively, then the variance of 6 observations x1,x2,,x5 and -50 is equal to

a
582.5
b
507.5
c
586.5
d
509.5

detailed solution

Correct option is B

It is given that    x1+x2+x3+x4+x55=10 and 15∑i=15 xi2−102=32⇒ ∑i=15 xi=50  and   15∑i=15 xi2−100=9⇒ ∑i=15 xi=50  and   ∑i=15 xi2=545Required variance =16∑i=15 xi2+(−50)2−∑i=15 xi+(−50)62                              =16{545+2500}−50−5062=30456=507.5

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