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If the middle term of ${(x^{2} + \frac{1}{x})}^{n}$ is $924 x^{6},$ then value of $n$ is

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Correct option is C

As there is just one middle term, n must be even and middle term is n2+1 th term, and it is given byTn/2+1=nCn/2x2n−n/21xn/2=nCn/2xn/2Now, nCn/2xn/2=924x6→n/2=6→n=12[Also, note that 12C6=924

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If the middle term of x2+1xn is 924 x6 , then value of n is

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If the middle term of ${(x^{2} + \frac{1}{x})}^{n}$ is $924 x^{6},$ then value of $n$ is