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Q.

If n∈N and sin⁡π2n+cos⁡π2n=n2then a  possible value of n is

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a

4

b

6

c

8

d

12

answer is B.

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Detailed Solution

n4=sin2⁡π2n+cos2⁡π2n+sin⁡2π2n⇒ sin⁡πn=n−44For n∈N,sin⁡πn>0 âˆ´ n−44>0 or n>4For n>4,πn<π2⇒sin⁡πn<1⇒ 0<14(n−4)<1⇒4
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