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a
n(a1-an)
b
(n-1)(a1-an)
c
na1an
d
(n-1)a1an
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Correct option is D
1a2−1a1=1a3−1a2=..=1an−1an-1=d since 1a1,1a2,1a3,.......1an are in A.Pa1a2=a1−a2d,a2a3=a2−a3d,.... ,an−1an=an−1−and⇒given expression=1da1−a2+a2−a3+…+an−1−an=a1−andbut nth term =1an=1a1+(n−1)d ⇒a1−ana1an=(n−1)d⇒a1−and=(n−1)a1an⇒given expression=(n−1)a1anSimilar Questions
Given that
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