Q.
If a1, a2, a3,...., an,... are in A.P. such that a4-a7+a10=m, then sum of the first 13 terms of the A.P. is
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a
10 m
b
12 m
c
13 m
d
15 m
answer is C.
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Detailed Solution
Let d be the common difference of the A.P.,then m=a4−a7+a10=a4+a10−a7 =a1+3d+3d=a1+6dNow, S13=1322a1+(13−1)d=13m.
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