Questions
If and are in A.P., then a value of can be
detailed solution
Correct option is B
As nC4,nC5 and nC6 are in A.P.2 nC5=nC4+nC6⇒ 2= nC4 nC5+ nC6 nC5=n!4!(n−4)!5!(n−5)!n!+n!6!(n−6)!5!(n−5)!n!⇒ 2=5n−4+n−56⇒n2−21n+98=0⇒ n=7,14.Similar Questions
is equal to
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