Q.
If n+1Cr+1:nCr:Cr−1 n−1=11:6:3, then nr =
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a
20
b
30
c
40
d
50
answer is D.
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Detailed Solution
Given, n+1Cr+1 nCr=116 or n+1r+1×nCr nCr=116or 6n+6=11r+11 or 6n−11r=5 (1)Also, nCr n−1Cr−1=63 or nr×n−1Cr−1 n−1Cr−1=63 or n=2r (2)From (1) and (2), r = 5 and n = 10,∴ nr=50
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