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If  nCr:nCr+1:nCr+2=1:2:3 then r is equal to

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a
5
b
4
c
3
d
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detailed solution

Correct option is B

21= nCr+1 nCr=n−rr+1and     32=n−r−1r+2⇒32=2(r+1)−1r+2               [∵n−r=2(r+1)]⇒3r+6=4r+2⇒r=4.


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 nCr+2nCr1+nCr2 is equal to


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