If nCr:nCr+1:nCr+2=1:2:3 then r is equal to
5
4
3
0
21= nCr+1 nCr=n−rr+1
and 32=n−r−1r+2
⇒32=2(r+1)−1r+2 [∵n−r=2(r+1)]⇒3r+6=4r+2⇒r=4.