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Q.

If A=[102−11−2021]  and  AdjA=[5x−2110−2−2y]  then (x,y) =

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a

(–4,1)

b

(4,1)

c

(–4,–1)

d

(4,–1)

answer is B.

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Detailed Solution

(54−2110−2−21) = (5x−2110−2−2y)                    (x,y) = (4,1)
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