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If n is even and  nC0<nC1<nC2<<nCr>nCr+1>>nCn then r =

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a
n2
b
n-12
c
n-22
d
n+22

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detailed solution

Correct option is A

By the given condition, it is clear that  nCr is the greatest among  nC0,nC1,…,nCn.Since n is even,∴ nCr is the greatest for r=n2∴ r=n2


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