If n is even and nC0<nC1<nC2<…<nCr>nCr+1>…>nCn then r =
n2
n-12
n-22
n+22
By the given condition, it is clear that nCr is the greatest among nC0,nC1,…,nCn.
Since n is even,
∴ nCr is the greatest for r=n2
∴ r=n2