If a1,a2,…,an,… form a G.P. then logan logan+1 logan+2logan+3 logan+4 logan+5logan+6 logan+7 logan+8 is equal to = , (where ai>0 , for all i≥1)
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a
0
b
1
c
2
d
3
answer is A.
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Detailed Solution
We have,an+12=anan+2⇒ 2log an+1=log an+log an+2Similarly,2logan+4=logan+3+logan+52logan+7=logan+6+logan+8Substituting these values in second column of determinant, we getΔ=12loganlogan+logan+2logan+2logan+3logan+3+logan+5logan+5logan+6logn+6+logan+8logan+8=12(0)=0 [Using C2→C2−C1−C3