If n>2, r>1 and the coefficients of (3r)th and (r + 2)th terms in the expansion of (1 + x)2n are equal, then
n = 2r
n = 3r
n = 2r + 1
n = 2r + 2
2nC3r−1=2nCr+1⇒3r−1+r+1=2n⇒n=2r.