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If $(2 + \sqrt{3})^{n} = I + f where I and n are positive$ $integers and 0 < f < 1, then (1 - f) (I + f)$

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Correct option is B

I+f=(2+3)n=2n+nC12n−13+nC22n−2(3)2+nC32n−3(3)3+… … (i) Now, 0<2−3<1⇒ 0<(2−3)n<1 Let (2−3)n=f′ where 0

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If (2+3)n=I+f where I and n are positive integers and 0<f<1, then (1−f)(I+f)

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If $(2 + \sqrt{3})^{n} = I + f where I and n are positive$ $integers and 0 < f < 1, then (1 - f) (I + f)$