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If $4 n Î± = Ï$ then the value of $\tan â¡ Î± \tan â¡ 2 Î± \tan â¡ 3 Î± â¦ \tan â¡ (2 n â 1) Î±$ is

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Correct option is C

tanâ¡(2nâ1)Î±=tanâ¡(Ï/2âÎ±)=cotâ¡Î± tanâ¡(2nâ2)Î±=cotâ¡2Î± and so on. So the required value is 1.

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If 4nÎ±=Ï then the value of tanâ¡Î± tanâ¡2Î± tanâ¡3Î±â¦tanâ¡(2nâ1)Î± is

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If $4 n Î± = Ï$ then the value of $\tan â¡ Î± \tan â¡ 2 Î± \tan â¡ 3 Î± â¦ \tan â¡ (2 n â 1) Î±$ is