If 4nα=Ï then the value of tanâ¡Î± tanâ¡2α tanâ¡3αâ¦tanâ¡(2nâ1)α is
-1
0
1
none of these
tanâ¡(2nâ1)α=tanâ¡(Ï/2âα)=cotâ¡Î±
tanâ¡(2nâ2)α=cotâ¡2α and so on.
So the required value is 1.