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If ‘n’ is an integer between 0 and 21, then the minimum value of n! (21 – n)! is

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a
9! 2!
b
10! 11!
c
20!
d
21!

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detailed solution

Correct option is B

n!(21−n)!=21!n!(21−n)!21!=21!1 21Cn=21! 21CnFor minimum value,  21Cn is maximum.Maximum value of  21Cn=21C21−1=21C10∴  Minimum value =21! 21C10=21!21!×10!11!=10!11!


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