If ‘n’ is an integer between 0 and 21, then the minimum value of n! (21 – n)! is
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a
9! 2!
b
10! 11!
c
20!
d
21!
answer is B.
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Detailed Solution
n!(21−n)!=21!n!(21−n)!21!=21!1 21Cn=21! 21CnFor minimum value, 21Cn is maximum.Maximum value of 21Cn=21C21−1=21C10∴ Minimum value =21! 21C10=21!21!×10!11!=10!11!