If ‘n’ is an integer between 0 and 21, then the minimum value of n!(21−n)! is
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a
9!2!
b
10!11!
c
20!
d
21!
answer is B.
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Detailed Solution
n!(21−n)!=21!.n!.(21−n)!21!=21!.121Cn=21!21Cn For minimum value 21Cn will be maximum. Maximum value of 21Cn= 21C10 ∴ Maximum value =21!21C10=21!21!×10!11!=10!11!