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If n=mC2 the value of  nC2 is given by

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a
m+1C4
b
m−1C4
c
m+2C4
d
3  m+3C4

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detailed solution

Correct option is D

We have,n=mC2=m(m−1)2∴ nC2=nn−1)2⇒nC2=m(m−1)4m(m−1)2−1⇒nC2=18m(m−1)m2−m−2⇒ nC2=18m(m−1)(m−2)(m+1)⇒ nC2=3124(n+1)m(m−1)(m−2)=3  m+3C4


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