If $$n(A)=4$$,$$n(B)=3$$,$$n(A$$×B×$$C)=24$$, then $$n(C)$$ is equal to

$$n(A$$×B×$$C)=n(A)n(B)n(C)$$ $$24=4$$×$$3$$×$$n(c)$$⇒$$n(c)=2$$

Relations XII

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If $n (A) = 4, n (B) = 3, n (A \times B \times C) = 24$ , then n(C) is equal to

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Solution

$n (A \times B \times C) = n (A) n (B) n (C) 24 = 4 \times 3 \times n (c) \Rightarrow n (c) = 2$

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