First slide
Introduction to Relations (XI) on Sets
Question

If n(A)=4, n(B)=3, n(A×B×C)=24, then n(C)=

Easy
Solution

n(A)=4, n(B)=3

n(A)×n(B)×n(C)=n(A×B×C)

4×3×n(C)=24n(C)=2412=2.

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