First slide
Introduction to Relations (XI) on Sets
Question

 If n(A)=4,n(B)=3,n(A×B×C)=24, then n(C)=

Easy
Solution

n(A)=4,n(B)=3n(A)×n(B)×n(C)=n(A×B×C)4×3×n(C)=24 n(C)=242=2

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App