If n(A)=4,n(B)=3,n(A×B×C)=24, then n(C)=
288
1
12
2
n(A)=4,n(B)=3n(A)×n(B)×n(C)=n(A×B×C)4×3×n(C)=24⇒ n(C)=242=2