If 49n+16n+λ is divisible by 64 for all n∈N, then the least negative integral value of λ, is

For n=1,we have49n+16n+λ=49+16+λ=65+λ=64+(λ+1), which is divisible by 64 if λ=−1.For n=2 we have49n+16n+λ=492+16×2+λ=2433+λ=(64×38)+(λ+1),which is divisible by 64 if λ=−1Hence, λ=−1.