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If n € N, n > 1, then value of
$\begin{array}{l} E = a -^{n} C_{1} (a - 1) +^{n} C_{2} (a - 2) + \dots . . . . + (- 1)^{n} {(a - n)}^{n} C_{n} is \end{array}$

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Correct option is B

Given equation can be rewritten asE=a nC0−nC1+nC2−…+(−1)n nCn+ nC1−(2) nC2+(3) nC3−…+(−1)n(n) nCn⇒E=0+0=0 by properties

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If n € N, n > 1, then value of E=a−nC1(a−1)+nC2(a−2)+…....+(−1)n(a−n)nCn is

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If n € N, n > 1, then value of
$\begin{array}{l} E = a -^{n} C_{1} (a - 1) +^{n} C_{2} (a - 2) + \dots . . . . + (- 1)^{n} {(a - n)}^{n} C_{n} is \end{array}$