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If $a_{n} = 2^{2^{n}} + 1$ , then for $n > 1$ last digit of $a_{n}$ is

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Correct option is B

For n=2,an=24+1=16+1=17. Assume that ak=22k+1=10m+7 where k>1 and m is some positive integer.

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If an=22n+1, then for n>1 last digit of an is

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If $a_{n} = 2^{2^{n}} + 1$ , then for $n > 1$ last digit of $a_{n}$ is