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If $a_{n} = 2^{2^{n}} + 1$ then for $n > 1$ , last digit of $a_{n}$ is

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Correct option is B

For n=2,an=24+1=16+1=17. . Assume That ak=22k+1=10m+7 where k>1and m is some positive integer.Now, ak+1=22k+1+1=22k2+1=(10m+6)2+1=1010m2+12m+3+7Thus, last digit of an is 7∀n>1

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If an=22n+1 then for n>1 , last digit of an is

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If $a_{n} = 2^{2^{n}} + 1$ then for $n > 1$ , last digit of $a_{n}$ is