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If $a_{n} = 2^{2^{n}} + 1$ then for n>1 , last digit of $a_{n}$ is

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Correct option is C

For n=2,an=222+1=16+1=17Assume that, ak=22k+1=10m+7, where k>1. and m is some positive integer.now, ak+1=2kk+1+1=2kk2+1=(10m+6)2+1=1010m2+12m+3+7Hence, last digit of an is 7,∀n>1

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If an=22n+1 then for n>1 , last digit of an is

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If $a_{n} = 2^{2^{n}} + 1$ then for n>1 , last digit of $a_{n}$ is