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If $n$ is odd and $^{n} C_{0} <^{n} C_{1} <^{n} C_{2} < \dots <^{n} C_{r}$ , then maximum possible value of $r$ is

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n−12

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Correct option is A

Use 2m+1Cr is maximum when r=m or r=m+1.

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If n is odd and nC0<nC1<nC2<…<nCr, then maximum possible value of r is

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If $n$ is odd and $^{n} C_{0} <^{n} C_{1} <^{n} C_{2} < \dots <^{n} C_{r}$ , then maximum possible value of $r$ is