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If $^{n + 5} p_{n + 1} = \frac{1}{2} (11) (n - 1) (^{n + 3} p_{n})$ then $n$ is equal to

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Correct option is D

12(11)(n−1)= n+5Pn+1 n+3Pn=(n+5)!4!×3!(n+3)!⇒ 12(11)(n−1)=14(n+5)(n+4)⇒ 22n−22=n2+9n+20⇒ n2−13n+42=0⇒n=6,7

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If n+5pn+1=12(11)(n−1) n+3pn then n is equal to

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If $^{n + 5} p_{n + 1} = \frac{1}{2} (11) (n - 1) (^{n + 3} p_{n})$ then $n$ is equal to