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Q.

If  n+5pn+1=12(11)(n−1) n+3pn then n is equal to

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a

10, 11

b

9, 10

c

8, 7

d

6,7

answer is D.

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Detailed Solution

12(11)(n−1)= n+5Pn+1 n+3Pn=(n+5)!4!×3!(n+3)!⇒ 12(11)(n−1)=14(n+5)(n+4)⇒    22n−22=n2+9n+20⇒    n2−13n+42=0⇒n=6,7
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