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If then the value of n is equal to
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Correct option is B
We have, 2n+1Pn−1:2n−1Pn=3:5⇒ 2n+1Pn−12n−1Pn=35⇒ (2n+1)!(n+2)!×(n−1)!(2n−1)!=35⇒ (2n+1)(2n)(n+2)(n+1)n=35 ⇒ 10(2n+1)=3(n+2)(n+1)⇒ 3n2−11n−4=0⇒ (n−4)(3n+1)=0⇒n=4Similar Questions
Let (where, [ . ] denotes greatest integer function) is equal to
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