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Q.

If n is a positive integer greater than unity and  z is a complex satisfying the equation zn=(z+1)n, then

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a

Re(z)<0

b

Re(z)>0

c

Re(z)=0

d

Z lies on x=−12

answer is D.

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Detailed Solution

zn=(z+1)n⇒|z|n=|z+1|n  or  |z|=|z+1|. So the distance of a point z remain same from (0,0) and (–1,0).So ,z lies on perpendicular bisector of line joining (0,0) and (–1,0).that is on x=−12
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If n is a positive integer greater than unity and  z is a complex satisfying the equation zn=(z+1)n, then