If n is a positive integer greater than unity and z is a complex satisfying the equation zn=(z+1)n, then
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a
Re(z)<0
b
Re(z)>0
c
Re(z)=0
d
Z lies on x=−12
answer is D.
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Detailed Solution
zn=(z+1)n⇒|z|n=|z+1|n or |z|=|z+1|. So the distance of a point z remain same from (0,0) and (–1,0).So ,z lies on perpendicular bisector of line joining (0,0) and (–1,0).that is on x=−12