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If nq and A=zC:zn=1 B=z:zq=1 then

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By Expert Faculty of Sri Chaitanya
a
A = B
b
A∩B={1}
c
B⊆A
d
A ⊂ B

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detailed solution

Correct option is D

q=pn for some p∈Nzq−1=znp−1=zn−1z(p−1)n+⋯+zn+1Every root of zn−1 is a root of zq−1 and every root of z(p−1)n+⋯+zn+1=0 is also a root of zq−1 Hence. A⊂B∣and A∩B=A


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