Q.
If a1,a2,a3…..an is sequence of +Ve numbers which are in AP with common difference 'd' & sec a1sec a 2+seca2seca3+…………..+secan−1secan=
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a
Tanasina1−sina2
b
Tanan−Tana1sind
c
n−1Tan1Tana2
d
Tana1−tanansind
answer is B.
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Detailed Solution
a2−a1=a3−a2=.....=an−1=d=1sindsina2−a1cosa1cosa2+sina3−a2cosa2cosa3+.....+sinan−an−1cos an−1cos8an=1sindtan a2−tana1+tana3−tan a2+....+tanan−tanan−1=tanan−tana1sind
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