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$If a_{1}, a_{2}, a_{3} \dots . . a_{n} is sequence of +Ve numbers which are in AP with$ $common difference 'd' &$
${sec a}_{1} {sec a}_{2} +$ $\sec a_{2} \sec a_{3} + \dots \dots \dots \dots . . + \sec a_{n - 1} \sec a_{n} =$

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Tanasina1−sina2

Tanan−Tana1sind

n−1Tan1Tana2

Tana1−tanansind

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detailed solution

Correct option is B

a2−a1=a3−a2=.....=an−1=d=1sindsina2−a1cosa1cosa2+sina3−a2cosa2cosa3+.....+sinan−an−1cos an−1cos8an=1sindtan a2−tana1+tana3−tan a2+....+tanan−tanan−1=tanan−tana1sind

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If a1,a2,a3…..an is sequence of +Ve numbers which are in AP with common difference 'd' & sec a1sec a 2+sec⁡a2sec⁡a3+…………..+sec⁡an−1sec⁡an=

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$If a_{1}, a_{2}, a_{3} \dots . . a_{n} is sequence of +Ve numbers which are in AP with$ $common difference 'd' &$
${sec a}_{1} {sec a}_{2} +$ $\sec a_{2} \sec a_{3} + \dots \dots \dots \dots . . + \sec a_{n - 1} \sec a_{n} =$