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Q.

If 110112011301⋯⋯·1n-101=17801 then the inverse of  1n01 is

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a

10121

b

1−1301

c

10131

d

1−12131

answer is B.

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Detailed Solution

Multiplying we get 11+2+3+⋯+n01=17801                           =1n(n-1)201  =17801   given ⇒n(n-1)2=78⇒n=13∴Inverse of 11301 =1−1301
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