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If $1^{2} + 2^{2} + \dots + n^{2} = 1015$ , then value of $n$ is

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Correct option is B

16n(n+1)(2n+1)=1015⇒(2n)(2n+1)(2n+2)=(28)(29)(30)⇒2n=28 or n=14

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If 12 + 22 + …+ n2 = 1015, then value of n is

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If $1^{2} + 2^{2} + \dots + n^{2} = 1015$ , then value of $n$ is