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Questions  

If A is non-singular and A25A+7I=0 then I=

a
17A−57A−1
b
17A+57A−1
c
15A+75A−1
d
15A−A−1

detailed solution

Correct option is C

A2−5A+7I=0 By right multiplication with A-1AAA-1-5AA-1+7IA-1=0 A-5I+7A-1=0⇒ 7A−1 =5I−A ⇒ I=75 A−1+15A

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