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 If A is a 3×3 non-singular matrix such that AAT=ATA and B=A1AT, then BBT=

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a
I+B
b
I
c
B−1
d
B−1T

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detailed solution

Correct option is B

Given, AAT=ATA and B=A−1ATBBT=A−1ATA−1ATT=A−1ATAA−1T ∵(AB)T=BTAT=A−1AATA−1T ∵AAT=ATA=IATA−1T ∵A−1A=I=ATA−1T=A−1AT ∵(AB)T=BTAT=IT=I


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