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By Expert Faculty of Sri Chaitanya
a
|A−1|=|A|
b
|A−1|=A−1
c
|A−1|=0
d
|A−1|==1|A|
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Correct option is D
Since, |A|≠0, therefore A−1 exist such that AA−1=I=A−1A ⇒ |AA−1|=|I| ⇒ |A||A−1|=1 ⇒|A−1|=1|A|
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