If non-zero vectors a→ and b→ are equally inclined to coplanar vector c→, then c→ can be
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a
|a→||a→|+2|b→|a→+|b→||a→|+|b→|b→
b
|b→||a→|+|b→|a→+|a→||a→|+|b→|b→
c
|a→||a→|+2|b→|a→+|b→||a→|+2|b→|b→
d
|b→|2|a→|+|b→|a→+|a→|2|a→|+|b→|b→
answer is B.
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Detailed Solution
Since a→ and b→ are equally inclined to c→, c→ must be of the form ta→|a→|+b→⌊b→∣.now,|b→||a→|+|b→|a→+|a→||a→|+|b→|b→=|a→||b→||a→|+|b→|a→|a→|+b→|b→|also,|b→|2|a→|+|b→|a→+|a→|2|a→|+|b→|b→=|a→||b→|2|a→|+|b→|a→|a→|+b→|b→|Other two vectors cannot be written in the formta→|a→|+b→|b→|